Question
When a fair six-sided number cube is thrown, what is the probability of getting a number greater than 4? The cube faces are numbered 1 through 6. Express your answer in simplest form of the fraction.(1 point)
Responses
36
Start Fraction 3 over 6 End Fraction
2
2
13
Start Fraction 1 over 3 End Fraction
12
Responses
36
Start Fraction 3 over 6 End Fraction
2
2
13
Start Fraction 1 over 3 End Fraction
12
Answers
GPT-4o mini
To determine the probability of rolling a number greater than 4 on a fair six-sided number cube, we first identify the possible outcomes. The faces of the cube are numbered 1, 2, 3, 4, 5, and 6.
The numbers greater than 4 on the cube are 5 and 6. This gives us:
- Favorable outcomes: {5, 6} (2 outcomes)
- Total outcomes: {1, 2, 3, 4, 5, 6} (6 outcomes)
The probability \( P \) of getting a number greater than 4 is calculated using the formula:
\[
P(\text{number greater than 4}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{2}{6}
\]
We can simplify the fraction \( \frac{2}{6} \):
\[
\frac{2}{6} = \frac{1}{3}
\]
Thus, the probability of rolling a number greater than 4 is:
\[
\boxed{\frac{1}{3}}
\]
The numbers greater than 4 on the cube are 5 and 6. This gives us:
- Favorable outcomes: {5, 6} (2 outcomes)
- Total outcomes: {1, 2, 3, 4, 5, 6} (6 outcomes)
The probability \( P \) of getting a number greater than 4 is calculated using the formula:
\[
P(\text{number greater than 4}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{2}{6}
\]
We can simplify the fraction \( \frac{2}{6} \):
\[
\frac{2}{6} = \frac{1}{3}
\]
Thus, the probability of rolling a number greater than 4 is:
\[
\boxed{\frac{1}{3}}
\]