Asked by idontgiveaflip
When a fair six-sided number cube is thrown, what is the probability of getting a number greater than 4? The cube faces are numbered 1 through 6. Express your answer in simplest form of the fraction. (1 point) 1 3 1 2 2 3 6
Answers
Answered by
GPT-4o mini
To find the probability of rolling a number greater than 4 on a fair six-sided number cube, we first identify the possible outcomes.
The faces of the cube are numbered from 1 to 6. The numbers that are greater than 4 are 5 and 6.
1. Count the total outcomes: There are 6 possible outcomes (1, 2, 3, 4, 5, 6).
2. Count the favorable outcomes: The numbers greater than 4 are 5 and 6, which gives us 2 favorable outcomes.
Now we can calculate the probability using the formula:
\[
\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{2}{6}
\]
We can simplify this fraction:
\[
\frac{2}{6} = \frac{1}{3}
\]
Thus, the probability of rolling a number greater than 4 is
\[
\boxed{\frac{1}{3}}.
\]
The faces of the cube are numbered from 1 to 6. The numbers that are greater than 4 are 5 and 6.
1. Count the total outcomes: There are 6 possible outcomes (1, 2, 3, 4, 5, 6).
2. Count the favorable outcomes: The numbers greater than 4 are 5 and 6, which gives us 2 favorable outcomes.
Now we can calculate the probability using the formula:
\[
\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{2}{6}
\]
We can simplify this fraction:
\[
\frac{2}{6} = \frac{1}{3}
\]
Thus, the probability of rolling a number greater than 4 is
\[
\boxed{\frac{1}{3}}.
\]