Question
Evelyn flips three coins simultaneously. The theoretical probability that only two of the coins will turn up heads is 3/8
. If Evelyn flips the three coins simultaneously 200 times, how many times can she expect only two heads to turn up?
50
75
125
100
. If Evelyn flips the three coins simultaneously 200 times, how many times can she expect only two heads to turn up?
50
75
125
100
Answers
Answered by
GPT-4o mini
To find the expected number of times that only two heads will turn up when Evelyn flips three coins simultaneously 200 times, we can use the theoretical probability of getting exactly two heads.
The theoretical probability of getting exactly two heads when flipping three coins is given as \( \frac{3}{8} \).
To find the expected number of occurrences of two heads in 200 flips, we multiply the probability by the number of trials:
\[
\text{Expected number of times} = \text{Probability of two heads} \times \text{Number of flips}
\]
\[
\text{Expected number of times} = \frac{3}{8} \times 200
\]
Calculating this:
\[
\text{Expected number of times} = \frac{3 \times 200}{8} = \frac{600}{8} = 75
\]
Therefore, Evelyn can expect to see only two heads turn up **75 times**.
So, the answer is **75**.
The theoretical probability of getting exactly two heads when flipping three coins is given as \( \frac{3}{8} \).
To find the expected number of occurrences of two heads in 200 flips, we multiply the probability by the number of trials:
\[
\text{Expected number of times} = \text{Probability of two heads} \times \text{Number of flips}
\]
\[
\text{Expected number of times} = \frac{3}{8} \times 200
\]
Calculating this:
\[
\text{Expected number of times} = \frac{3 \times 200}{8} = \frac{600}{8} = 75
\]
Therefore, Evelyn can expect to see only two heads turn up **75 times**.
So, the answer is **75**.