Asked by Scott
Evaluate the integral e^x sin4x dx.
I know the answer is 1/17 e^x sin4x - 4/17 e^x cos4x + C but I don't know how to solve it out.
I know the answer is 1/17 e^x sin4x - 4/17 e^x cos4x + C but I don't know how to solve it out.
Answers
Answered by
MathMate
Use integration by parts:
I=∫e<sup>x</sup>sin(4x)dx
=e<sup>x</sup>sin(4x)-4∫e<sup>x</sup>cos(4x)dx
=e<sup>x</sup>sin(4x)-4e<sup>x</sup>cos(4x)-16∫e<sup>x</sup>sin(4x)dx
=e<sup>x</sup>sin(4x)-4e<sup>x</sup>cos(4x)-16I
Solve for I to get the above results.
I=∫e<sup>x</sup>sin(4x)dx
=e<sup>x</sup>sin(4x)-4∫e<sup>x</sup>cos(4x)dx
=e<sup>x</sup>sin(4x)-4e<sup>x</sup>cos(4x)-16∫e<sup>x</sup>sin(4x)dx
=e<sup>x</sup>sin(4x)-4e<sup>x</sup>cos(4x)-16I
Solve for I to get the above results.
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