Ask a New Question

Asked by Dave

Evaluate the integral of e^(1/x) / x^2 from [1,2].

I let u =1/x, but then I am stuck because I am not sure what is the derivative of 1/x is?

The answer in the book is e- sqrt(e)
8 years ago

Answers

Answered by Steve
let u=1/x
du = -1/x^2 dx

∫e^(1/x)/x^2 dx
= -∫e^u du
= -e^u = -e^(1/x) [1,2]
= -e^(1/2) + e^(1/1)
...
8 years ago

Related Questions

Evaluate the following integrals by using appropriate method : ∫cos⁡ ^3 ( 2x-5 )dx help evaluate (integral) xe^2x dx A. 1/6x^2 e^3x+C B. 1/2xe^2x-1/2e^2x+C C. 1/2xe^2x-1/4e^2x+C D. 1... evaluate the integral from 4 to 3. x/2x^2-6dx Evaluate the integral. ∫ 28e^(√7x)/(2√x) dx Evaluate the integral. ∫5sec^(4)x dx I got 5(secx+tanx)^(5)+C. is it right. Evaluate the integral: (cos(2-3x) - tan(5-3x))dx Evaluate the integral using u substitution ((y^3)/((1-y^2)^2))dy 1.Evaluate the integral. (Use C for the constant of integration.) integral ln(sqrtx)dx 2. Use the m...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use