Asked by K
                Help on part "c":
The forensic technician at a crime scene has just prepared a luminol stock solution by adding 19.0g of luminol into a total volume of 75.0mL of H2O.
a)What is the molarity of the stock solution of luminol?
anwer I got: molarity of luminol solution = 1.43M
b)Before investigating the scene, the technician must dilute the luminol solution to a concentration of 6.00×10−2 M. The diluted solution is then placed in a spray bottle for application on the desired surfaces.
I cannot get the correct answer for "c"...I have tried: 172mL,11.9mL, and 1.19*10^4. The only other possibility that I can come up with is: 83.9mL. Would this one be correct?...Or...am I still completely out to lunch???
c)How many moles of luminol are present in 2.00 L of the diluted spray?
anwer I got: moles of luminol =
0.120mol
What volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B)?
Express your answer in milliliters.
            
            
        The forensic technician at a crime scene has just prepared a luminol stock solution by adding 19.0g of luminol into a total volume of 75.0mL of H2O.
a)What is the molarity of the stock solution of luminol?
anwer I got: molarity of luminol solution = 1.43M
b)Before investigating the scene, the technician must dilute the luminol solution to a concentration of 6.00×10−2 M. The diluted solution is then placed in a spray bottle for application on the desired surfaces.
I cannot get the correct answer for "c"...I have tried: 172mL,11.9mL, and 1.19*10^4. The only other possibility that I can come up with is: 83.9mL. Would this one be correct?...Or...am I still completely out to lunch???
c)How many moles of luminol are present in 2.00 L of the diluted spray?
anwer I got: moles of luminol =
0.120mol
What volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B)?
Express your answer in milliliters.
Answers
                    Answered by
            bobpursley
            
    I didn't check a), I assumed you have.
Diluting 1.43 to .06 M is a ratio of 23.8 to 1. So add 22.8 parts water, one part the original solution. How many moles in 2L? 2L*.06M= .120moles
What volume in stock solution has .120moles? volume=moles/conc=.120/1.43M = 83.9ml
    
Diluting 1.43 to .06 M is a ratio of 23.8 to 1. So add 22.8 parts water, one part the original solution. How many moles in 2L? 2L*.06M= .120moles
What volume in stock solution has .120moles? volume=moles/conc=.120/1.43M = 83.9ml
                    Answered by
            K
            
    this answer, 83.9mL worked...thank you for the guidance.
    
                    Answered by
            hany
            
    The forensic technician at a crime scene has just prepared a luminol stock solution by adding 14.0 g  of luminol into a total volume of 75.0 mL of .
What is the molarity of the stock solution of luminol?
    
What is the molarity of the stock solution of luminol?
                    Answered by
            lia
            
    14.0g of luminol total volume 75 ml
is 1.05 molarity
    
is 1.05 molarity
                    Answered by
            parisa
            
    You carefully weigh out 20.00 of powder and add it to 81.00 of solution. You notice bubbles as a reaction takes place. You then weigh the resulting solution and find that it has a mass of 92.80 . The relevant equation is
Assuming no other reactions take place, what mass of was produced in this reaction?
                    Answered by
            FRED.
            
    A) .12 Mol
B) 79.7 ml
    
B) 79.7 ml
                    Answered by
            Anonymous
            
    106mL
    
                    Answered by
            QUEEN POTATO
            
    this is the year I am born HAHA
    
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