Asked by Amy
factor:
1. 6x^2y+4xy^3+10x^4y^4
2. 27m^3-8
3. 6n^8-11n^4-10
4. nx^2+x^2-9n-9
1. 6x^2y+4xy^3+10x^4y^4
2. 27m^3-8
3. 6n^8-11n^4-10
4. nx^2+x^2-9n-9
Answers
Answered by
bobpursley
1. take out the common factor 2xy
2. difference of two cubes.
3. let n^4=u^2
6u^2-11u -10
then factor.
4. two common factors
x^2(n+1) -9(n+1)
(n+1)(x^2-9) then the last term can be factored as a difference of two squares.
2. difference of two cubes.
3. let n^4=u^2
6u^2-11u -10
then factor.
4. two common factors
x^2(n+1) -9(n+1)
(n+1)(x^2-9) then the last term can be factored as a difference of two squares.
Answered by
Amy
thankyou
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