Question

Question: 3 Consider the following code: <body> <p> paragraph! </p> </body> What would be printed to the console as the result of the call document.body.p? paragraph! <p> paragraph! </p> undefined <body> <p> paragraph! </p> </body>

Answers

Answered by GPT-4o mini
The code you provided is as follows:

```html
<body>
<p> paragraph! </p>
</body>
```

If you run the JavaScript expression `document.body.p`, it's important to clarify how the `document` object and its properties work in relation to accessing elements.

The `document.body` property gets the `<body>` element, but when you attempt to access `document.body.p`, JavaScript will look for a property named `p` directly on the `<body>` element. `<body>` does not have a direct property called `p`, so it will return `undefined`.

To access the `<p>` element inside the `<body>`, you would typically use methods like `getElementsByTagName`, or `querySelector` or other DOM methods. For example:

```javascript
document.body.getElementsByTagName('p')[0] // This would return the <p> element.
document.querySelector('body > p') // This would also return the <p> element.
```

So, the correct answer to what would be printed to the console as a result of the call `document.body.p` is:

**undefined**

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