To find the probability of getting only one head when two coins are tossed simultaneously, you can use the formula for probability:
\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \]
From the data provided:
- The number of times only one head was obtained is 265.
- The total number of tosses is 500.
Now, plug the values into the formula:
\[ \text{Probability of getting only one head} = \frac{265}{500} \]
Now, simplify the fraction:
\[ \frac{265}{500} = 0.53 \]
Thus, the probability of getting only one head is \( 0.53 \) or \( 53% \).