The table shows the results of three coins tossed simultaneously 200 time

Question

outcome:
No heads 20.
1 head 77.
2 heads 72.
3 heads 23

Based on the data what is the experimental probability of of only 2 heads showing up?

Answer 1

To find the experimental probability of getting exactly 2 heads when three coins are tossed, you can use the formula for experimental probability:

\[ P(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of trials}} \]

In this case, the number of favorable outcomes (where exactly 2 heads show up) is 72, and the total number of trials (the total number of times the coins were tossed) is 200.

Using these values:

\[ P(\text{2 heads}) = \frac{72}{200} \]

Now, we can simplify this fraction:

\[ P(\text{2 heads}) = \frac{72 \div 8}{200 \div 8} = \frac{9}{25} \]

So, the experimental probability of getting exactly 2 heads is \(\frac{9}{25}\) or 0.36 (when expressed as a decimal).