Asked by Sam
two long separated friends, june and bill, spot each other in an airport terminal from a distance of 25m. they start to run towards each other. bill accerlates at a constant rate of 1.5m/s2, and june at a constant rate of 1.2m/s2. how far from junes inital postition do they meet?
Answers
Answered by
bobpursley
first, find time to meet.
25=1/2 (1.5+1.2)t^2
solve for t.
then, distance from junes initial position is d=1/2 1.2*t^2
25=1/2 (1.5+1.2)t^2
solve for t.
then, distance from junes initial position is d=1/2 1.2*t^2
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