5t + 35t = 4600m,
40t = 4600,
t = 115s. = 1.92 min.
Car A and Car B are separated by 4600 meters and travel toward each other. If Car A has a speed of 5 m/s and Car B has a speed of 35 m/s, how much time will pass before they pass each other?
2 answers
5t + 35t = 4600m,
40t = 4600,
t = 115s. = 1.92min.
40t = 4600,
t = 115s. = 1.92min.