To find the percentage of sugar and water in the syrup, we first need to determine the total mass of the syrup.
-
Total mass of the syrup: \[ \text{Total mass} = \text{mass of sugar} + \text{mass of water} = 84 , \text{grams} + 156 , \text{grams} = 240 , \text{grams} \]
-
Percentage of sugar in the syrup: \[ \text{Percentage of sugar} = \left( \frac{\text{mass of sugar}}{\text{total mass}} \right) \times 100 = \left( \frac{84}{240} \right) \times 100 \] \[ \text{Percentage of sugar} = 0.35 \times 100 = 35% \]
-
Percentage of water in the syrup: \[ \text{Percentage of water} = \left( \frac{\text{mass of water}}{\text{total mass}} \right) \times 100 = \left( \frac{156}{240} \right) \times 100 \] \[ \text{Percentage of water} = 0.65 \times 100 = 65% \]
In conclusion, the syrup is:
- 35% sugar
- 65% water