what is the area of the sector of a circle with θ = 75 degrees and a radius of 4 feet? include pi in your calculation

1 answer

To find the area of a sector of a circle, you can use the formula:

\[ \text{Area of the sector} = \frac{\theta}{360} \times \pi r^2 \]

where:

  • \( \theta \) is the angle in degrees,
  • \( r \) is the radius of the circle.

In this case, \( \theta = 75 \) degrees and \( r = 4 \) feet.

Plugging in the values:

\[ \text{Area of the sector} = \frac{75}{360} \times \pi \times (4)^2 \]

Calculating \( (4)^2 \):

\[ (4)^2 = 16 \]

So now we have:

\[ \text{Area of the sector} = \frac{75}{360} \times \pi \times 16 \]

Now simplify \( \frac{75}{360} \):

\[ \frac{75}{360} = \frac{75 \div 15}{360 \div 15} = \frac{5}{24} \]

Thus, the area becomes:

\[ \text{Area of the sector} = \frac{5}{24} \times \pi \times 16 \]

Now multiply \( \frac{5}{24} \) by 16:

\[ \frac{5 \times 16}{24} = \frac{80}{24} = \frac{10}{3} \]

Now we can finalize the area of the sector:

\[ \text{Area of the sector} = \frac{10}{3} \pi \text{ square feet} \]

So, the area of the sector is:

\[ \frac{10}{3} \pi \text{ square feet} \]