Asked by andrea

The two angled ropes used to support the crate in the figure below an withstand a maximum tension of 1300 N before they break. The left angle is 30dregres, and the right angle is 45degrees. What is the largest mass the ropes can support? m=?
Answered by bobpursley
look at the horizonal (I assume the angles are measured to the horizontal).

Tleft*cos30=Tr*cos45
and the vertical..
Tleft*sin30+Tr*cos45=mass*g

so solve for Tleft in the first equation:
tleft=Trcos45/cos30
Trcos45/cos30 *sin30+Trcos45=mg
solve for Tr. Put that in the equation for tleft. Then set it equal , 1300N
thensolve for mass.
Answered by andrea
is the answer 123.79 kg? or Newtons? thank you for the help
Answered by Don
it should be in kg.
Answered by Anonymous
..... isnt it Trcos45-Tleftcos30= 0

Tr = Tleftcos30/cos45?
Answered by Selena
170kg
Answered by Henry
T1*sin(180-30) + T2*sin30=-Mg*sin270.
1300*sin150 + 1300*sin30 = -Mg*sin270
650 + 650 = Mg.
Mg = 1300 N.
M = 1300/9.8 = 132.7 kg.

Answered by Henry
Correction:
T1*sin(180-30) + T2*sin45 = -Mg*sin270.

1300*sin150 + 1300*sin45 = Mg.
650 + 919.2 = Mg.
Mg = 1569.2 N.
M = 1569.2/9.8 = 160 Kg.
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