Question
two ropes are attached to a 200. kg sled. A 490. newton dog attached to on eo the ropes applies a force of 300. N b north of the rope. A 35.0 kg dog attached to the second rope applies a force of 125 N b 36.9 degrees south of west to the rope. Calculate the net force applies to the sled. (vector diagrams reequired)
Answers
Fy = North pull = 300 - 125 sin 36.9
Fx = East pull = -125 cos 36.9
|F| = sqrt(Fx^2+Fy^2)
tan angle north of east = Fy/Fx
remember in quadrant 2
Fx = East pull = -125 cos 36.9
|F| = sqrt(Fx^2+Fy^2)
tan angle north of east = Fy/Fx
remember in quadrant 2