Question
Suppose someone spins the spinner shown in the figure once. Find the given probability.
red
red
blue
blue
blue
purpl e
.
.
.
Question content area right
Part 1
The probability that the arrow will stop on a section that is labeled
enter your response here is one sixth
The probability that the arrow will stop on a section that is labeled
enter your response here is one half
The probability that the arrow will stop on a section that is labeled
enter your response here is one third
red
red
blue
blue
blue
purpl e
.
.
.
Question content area right
Part 1
The probability that the arrow will stop on a section that is labeled
enter your response here is one sixth
The probability that the arrow will stop on a section that is labeled
enter your response here is one half
The probability that the arrow will stop on a section that is labeled
enter your response here is one third
Answers
GPT-4o mini
To calculate the probabilities based on the spinner you described, we need to analyze the number of sections labeled with each color.
**Assumptions based on common examples, since no specific figures or numbers of sections were provided:**
Let's assume the spinner has the following sections based on your description:
- 2 sections labeled red
- 3 sections labeled blue
- 1 section labeled purple
This gives us a total of \(2 + 3 + 1 = 6\) sections.
### Part 1: Probability for each color
1. **The probability that the arrow will stop on a section that is labeled red:**
- The number of red sections = 2
- Total sections = 6
- Probability (red) = Number of red sections / Total sections = \( \frac{2}{6} = \frac{1}{3} \)
2. **The probability that the arrow will stop on a section that is labeled blue:**
- The number of blue sections = 3
- Probability (blue) = Number of blue sections / Total sections = \( \frac{3}{6} = \frac{1}{2} \)
3. **The probability that the arrow will stop on a section that is labeled purple:**
- The number of purple sections = 1
- Probability (purple) = Number of purple sections / Total sections = \( \frac{1}{6} \)
### Answers
- The probability that the arrow will stop on a section that is labeled **red** is **one third**.
- The probability that the arrow will stop on a section that is labeled **blue** is **one half**.
- The probability that the arrow will stop on a section that is labeled **purple** is **one sixth**.
If the spinner configuration is different, feel free to provide the exact numbers of each color section, and I will adjust the calculations accordingly!
**Assumptions based on common examples, since no specific figures or numbers of sections were provided:**
Let's assume the spinner has the following sections based on your description:
- 2 sections labeled red
- 3 sections labeled blue
- 1 section labeled purple
This gives us a total of \(2 + 3 + 1 = 6\) sections.
### Part 1: Probability for each color
1. **The probability that the arrow will stop on a section that is labeled red:**
- The number of red sections = 2
- Total sections = 6
- Probability (red) = Number of red sections / Total sections = \( \frac{2}{6} = \frac{1}{3} \)
2. **The probability that the arrow will stop on a section that is labeled blue:**
- The number of blue sections = 3
- Probability (blue) = Number of blue sections / Total sections = \( \frac{3}{6} = \frac{1}{2} \)
3. **The probability that the arrow will stop on a section that is labeled purple:**
- The number of purple sections = 1
- Probability (purple) = Number of purple sections / Total sections = \( \frac{1}{6} \)
### Answers
- The probability that the arrow will stop on a section that is labeled **red** is **one third**.
- The probability that the arrow will stop on a section that is labeled **blue** is **one half**.
- The probability that the arrow will stop on a section that is labeled **purple** is **one sixth**.
If the spinner configuration is different, feel free to provide the exact numbers of each color section, and I will adjust the calculations accordingly!