Question

Suppose someone spins the spinner shown in the figure once. Find the given probability.
red
red
yellow
yellow
yellow
gr e e n
.
.
.
Question content area right
Part 1
The probability that the arrow will stop on a section that is labeled
  
enter your response here is one sixth
The probability that the arrow will stop on a section that is labeled
  
enter your response here is one half
The probability that the arrow will stop on a section that is labeled
  
enter your response here is one third

Answer 1

To find the probabilities associated with the spinner based on the colors you provided, we first need to know the number of sections of each color on the spinner.

Assuming the spinner has the following sections based on your description:

- Red: 2 sections
- Yellow: 3 sections
- Green: 1 section

This gives us a total of 2 (red) + 3 (yellow) + 1 (green) = 6 sections.

Now, we can find the probabilities for each color.

1. **Probability for Red:**
\[
P(\text{Red}) = \frac{\text{Number of Red sections}}{\text{Total sections}} = \frac{2}{6} = \frac{1}{3}
\]

2. **Probability for Yellow:**
\[
P(\text{Yellow}) = \frac{\text{Number of Yellow sections}}{\text{Total sections}} = \frac{3}{6} = \frac{1}{2}
\]

3. **Probability for Green:**
\[
P(\text{Green}) = \frac{\text{Number of Green sections}}{\text{Total sections}} = \frac{1}{6}
\]

Using this setup, here are the filled-in answers for your problems:

- The probability that the arrow will stop on a section that is labeled **Red** is **one third**.
- The probability that the arrow will stop on a section that is labeled **Yellow** is **one half**.
- The probability that the arrow will stop on a section that is labeled **Green** is **one sixth**.