Asked by Jessica
A 8 lb rabbit needs 300ug/kg of a 1% solution. How many ml should be given
Answers
Answered by
MathMate
First convert all numbers to consistent units.
1 lb = 0.4536 kg
1 μg = 1/1000000 g
Therefore
8 lbs = 8*0.4536 kg = 3.63 kg
medication required
= 300 * 3.63 μg
= 300 * 3.63 / 1000000 g
= 0.0011 g
Volume of 1% solution required
= 0.0011 / 0.01 ml
= 0.11 ml
1 lb = 0.4536 kg
1 μg = 1/1000000 g
Therefore
8 lbs = 8*0.4536 kg = 3.63 kg
medication required
= 300 * 3.63 μg
= 300 * 3.63 / 1000000 g
= 0.0011 g
Volume of 1% solution required
= 0.0011 / 0.01 ml
= 0.11 ml
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