Asked by april
turtle goes 0.50m/s rabbit goes 3.0m/s^2.. rabbit gives turtle 195 seconds head start. how long will it take for hare to catch turtle?
195*.5=97.5m
+amount covered while rabbit is catching up
195*.5=97.5m
+amount covered while rabbit is catching up
Answers
Answered by
Henry
d = 0.5m/s * 195s = 97.5 m. Head-start.
d2 = d1 + 195 m.
0.5*a*t^2 = r*t + 195
0.5*3*t^2 = 0.5*t + 195
1.5t^2 - 0.5t - 195 = 0
Use Quadratic formula.
t = 11.6 s.
d2 = d1 + 195 m.
0.5*a*t^2 = r*t + 195
0.5*3*t^2 = 0.5*t + 195
1.5t^2 - 0.5t - 195 = 0
Use Quadratic formula.
t = 11.6 s.
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