Asked by Piper

1. A rabbit and a turtle are practicing for their big race. The rabbit covers a 30.0 m practice course in 5.00 seconds; the turtle covers the same distance in 120 seconds. If the actual race is run on a 96.0 m course, by how many seconds will the rabbit beat the turtle?

2. Two cyclist race with nearly uniform speed on a 500. m course. The blue bicycle crosses the finish line 2.00 s ahead of the red bicycle. If the red bicycle maintained an average speed of 10.0 m/s, what was the average speed of the blue bicycle?
Answered by Henry
1. r1=d/t = 30m/5s = 6 m/s.=Speed of rabbit

r2=30m/120s = 0.25 m/s.=Speed of turtle

T1 = d/r1 = 96/6 = 16 s.=Rabbit's time.

T2 = d/r2 = 96/0.25 = 384 s. = Turtle's
time.

T2 - T1 = 384 - 16 = 368 s.

2. T2 = d/r2 = 500/10 = 50 s. = Time of
red bicycle.

d = r1 * T1 = 500
r1 = 500/T1 = 500/(50-2) = 10.42 m/s. =
Speed of blue bicycle.




Answered by Piper
Thank you
Answered by Henry
Glad I could help.
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