Question

A cannon sends a projectile towards a target
a distance 1250 m away. The initial velocity
makes an angle 40◦ with the horizontal. The
target is hit.
The acceleration of gravity is 9.8 m/s2 .
What is the magnitude of the initial veloc-
ity?
Answer in units of m/s.

Answer 1

d = V^2(sin^2(µ)/2g

d = 1250m

µ = 40º

g = 9.8m^s^2

Solve for V

Answer 2

is that sin square?