d = V^2(sin^2(µ)/2g
d = 1250m
µ = 40º
g = 9.8m^s^2
Solve for V
A cannon sends a projectile towards a target
a distance 1250 m away. The initial velocity
makes an angle 40◦ with the horizontal. The
target is hit.
The acceleration of gravity is 9.8 m/s2 .
What is the magnitude of the initial veloc-
ity?
Answer in units of m/s.
2 answers
is that sin square?
0 answers