Question

Intrinsic - 5.5, 5.5, 5.2, 5.3, 4.7, 5.5, 5.2, 5.3, 4.7, 5.4, 6.2, 5.2, 5.3, 4.7, 5.4, 6.2, 5.2, 5.5, 5.2, 5.3, 4.7, 5.4, 6.2, 5.2, 5.6 Extrinsic6.8, 5.5, 4.6, 5.7,5.6, 5.5, 4.6, 5.7, 5.6, 5.6, 5.5, 4.6, 5.7, 5.6, 5.6, 5.5, 4.6, 5.5, 4.6, 5.7 5.6, 5.6, 5.5,4.6, 4.8 1. Perform a two-tailed hypothesis test on both the intrinsic and the extrinsic variable’s data, using a .05 significance level. 2. Begin by creating a null and an alternate statement. 3. Identify the significance level, the test statistic, and the critical value. State whether you are rejecting or failing to reject the null hypothesis statement

Answer 1

From your data:

Ho: mean 1 = mean 2
Ha: mean 1 ≠ mean 2

P = .05

Z = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√(n-1)

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to that Z score.