Asked by Megan
Find the volume in liters of 0.452 M manganese(II) sulfate that contains 54.5 g of solute?
Answers
Answered by
TutorCat
I'd divide 54.5 g by the molar mass to find the number moles of manganese(II) sulfate (MnSO4).
Molarity (M) = moles of solute/ volume in liters
Molarity (M) = moles of solute/ volume in liters
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