Asked by Anna
lim as x approaches 0 of tanx/x
Answers
Answered by
Anna
I broke that down into the lim of sinx/(xcosx)
Answered by
Damon
tan x = x + x^3/3 + x^5/15 .... smaller and smaller for x-->0
so
(1/x) tan x = 1 + x^2/3 + x^4/15 .....
which looks like one for small x
so
(1/x) tan x = 1 + x^2/3 + x^4/15 .....
which looks like one for small x
Answered by
Anna
sorry i should have put lim tan(x)/x
Answered by
Damon
I broke that down into the lim of sinx/(xcosx)
sin x --> x + x^3/3! + x^5/5! ...
cos x --> 1 -x^2/2! + x^4/4! ....
so
(x+ x^3/3! ...)
-----------------
(x -x/2! ....)
x/x
1
sin x --> x + x^3/3! + x^5/5! ...
cos x --> 1 -x^2/2! + x^4/4! ....
so
(x+ x^3/3! ...)
-----------------
(x -x/2! ....)
x/x
1
Answered by
Anna
how did you get all of those x's with exponents?
Answered by
Damon
The series for sine and cosine
Answered by
Damon
The point is that tan x approaches x for small x and therefore (1/x)tan x becomes 1/1 or 1 as x goes to zero.
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