Asked by Ashley
What minimum frequency of light is required to ionize potassium?The energy required to ionize potassium is 419kJ/mol?
Answers
Answered by
DrBob222
E = h*frequency
I would convert 419 kJ/mol to J, then divide by 6.022 x 10^23 to convert to J/atom, substitute into the equation and solve for frequency.
I would convert 419 kJ/mol to J, then divide by 6.022 x 10^23 to convert to J/atom, substitute into the equation and solve for frequency.
Answered by
Alex
I got 4.6102*10^-6 and it is wrong...Can you step me through the problem?
Answered by
Matt
419 kj into jules =
419000
Divide by avogadro's number
419000/6.022e23
Divide that by Planck's Constant for the answer.
419000
Divide by avogadro's number
419000/6.022e23
Divide that by Planck's Constant for the answer.
Answered by
Sophie
V=E/h so (149000/(6.026x10^-34)(6.022x10^23) =1.05x10^15. s^-1
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