Question

A girl notices a ball moving straight upward just outside her window. The ball is visible for 0.25 seconds as it moves a distance of 1.05m from the bottom to the top of the window.
How long does it take before the ball reappears?
What is the greatest height of the ball above the top of the window?

I found the velocity of the ball to be 5.4 m/s upward. And I know that at the greatest height the velocity of the ball will equal zero, but I'm not really sure where to go beyond that.

Answer 1

Ok, above the window

Vf=0=Vi-9.8t
where Vi is the velocity you found.
solve for time t to the top. How long will it take to reapperar? 2t.
greatest height?
h=vi*t-4.9t^2