Asked by Nkateko
A girl throws a ball of 0,2 kg mass vertically upwards with an initial velocity of 12 metres per second
Calculate the maximum height reached by the ball above the girls hand
Calculate the maximum height reached by the ball above the girls hand
Answers
Answered by
oobleck
v^2 = 2as, so
12^2 = 2*9.81 s
s = 144/19.62
you can do this using the usual
v = 12-gt = 0
and then using that value of t in
s = 1/2 gt^2
12^2 = 2*9.81 s
s = 144/19.62
you can do this using the usual
v = 12-gt = 0
and then using that value of t in
s = 1/2 gt^2
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