Question

A girl throws a ball of 0,2 kg mass vertically upwards with an initial velocity of 12 metres per second
Calculate the maximum height reached by the ball above the girls hand

Answer 1

v^2 = 2as, so
12^2 = 2*9.81 s
s = 144/19.62

you can do this using the usual
v = 12-gt = 0
and then using that value of t in
s = 1/2 gt^2