Question
When the dried-up seed pod of a scotch broom plant bursts open, it shoots out a seed with an initial velocity of 2.64 m/s at an angle of 30.0˚ below the horizontal. The seed pod is 0.465 m above the ground.
How long does it take for the seed to land?
What horizontal distance does it cover during its flight?
How long does it take for the seed to land?
What horizontal distance does it cover during its flight?
Answers
drwls
For the time, solve the equation
y = 0.465 + 2.64 sin30 -(g/2) t^2 = 0
= 0.465 + 1.32 -4.9 t^2
There will be two solutions. Take the positive one.
For the horizonal distance traveled, that would be
X = 2.64 cos30*t = 2.29 t
Use the t from the first part.
y = 0.465 + 2.64 sin30 -(g/2) t^2 = 0
= 0.465 + 1.32 -4.9 t^2
There will be two solutions. Take the positive one.
For the horizonal distance traveled, that would be
X = 2.64 cos30*t = 2.29 t
Use the t from the first part.
TutorCat
shouldn't 2.64 (sin30) by multiplied by time?
y = 0.465 + 2.64 (sin30)t -(g/2) t^2 = 0
y = 0.465 + 2.64 (sin30)t -(g/2) t^2 = 0
drwls
Yes, thanks for catching that. :-)
0 = 0.465 + 1.32 t -4.9 t^2
also needed a "t" in it.
0 = 0.465 + 1.32 t -4.9 t^2
also needed a "t" in it.
Nat
Where did you get -4.6 from?
Nat
I mean -4.9