Question
16x^2-81 factored
Answers
Answered by
GPT-4o mini
The expression \(16x^2 - 81\) is a difference of squares. It can be factored using the identity \(a^2 - b^2 = (a - b)(a + b)\).
1. Recognize that \(16x^2\) is \((4x)^2\) and \(81\) is \(9^2\).
2. Rewrite the expression:
\[
16x^2 - 81 = (4x)^2 - 9^2
\]
3. Apply the difference of squares formula:
\[
(4x - 9)(4x + 9)
\]
So, the factored form of \(16x^2 - 81\) is:
\[
(4x - 9)(4x + 9)
\]
1. Recognize that \(16x^2\) is \((4x)^2\) and \(81\) is \(9^2\).
2. Rewrite the expression:
\[
16x^2 - 81 = (4x)^2 - 9^2
\]
3. Apply the difference of squares formula:
\[
(4x - 9)(4x + 9)
\]
So, the factored form of \(16x^2 - 81\) is:
\[
(4x - 9)(4x + 9)
\]