Question
Radio waves travel at the speed of light, 3 x 108 meters/second. If your favorite radio station is
broadcast at a frequency of 101.5 megahertz (101.5 x 106 hertz), what is the wavelength of the radio
waves?
Answers below:
0.338 m
0.300 m
2.96 m
0.030 m
broadcast at a frequency of 101.5 megahertz (101.5 x 106 hertz), what is the wavelength of the radio
waves?
Answers below:
0.338 m
0.300 m
2.96 m
0.030 m
Answers
Answered by
GPT-4o mini
To calculate the wavelength of the radio waves, we can use the formula that relates the speed of light (c), frequency (f), and wavelength (λ):
\[
c = f \cdot \lambda
\]
Where:
- \( c \) is the speed of light (approximately \( 3 \times 10^8 \) meters per second),
- \( f \) is the frequency in hertz,
- \( \lambda \) is the wavelength in meters.
We can rearrange the formula to solve for wavelength:
\[
\lambda = \frac{c}{f}
\]
Given the frequency of the radio station is \( 101.5 \) megahertz, we first convert that into hertz:
\[
f = 101.5 \times 10^6 \text{ Hz}
\]
Now, we substitute the values into the wavelength formula:
\[
\lambda = \frac{3 \times 10^8 \text{ m/s}}{101.5 \times 10^6 \text{ Hz}}
\]
Calculating this gives:
\[
\lambda \approx \frac{3 \times 10^8}{101.5 \times 10^6} \approx \frac{3 \times 10^8}{1.015 \times 10^8} \approx 2.95 \text{ m}
\]
After rounding, we find:
\[
\lambda \approx 2.96 \text{ m}
\]
Therefore, the correct answer is:
**2.96 m**
\[
c = f \cdot \lambda
\]
Where:
- \( c \) is the speed of light (approximately \( 3 \times 10^8 \) meters per second),
- \( f \) is the frequency in hertz,
- \( \lambda \) is the wavelength in meters.
We can rearrange the formula to solve for wavelength:
\[
\lambda = \frac{c}{f}
\]
Given the frequency of the radio station is \( 101.5 \) megahertz, we first convert that into hertz:
\[
f = 101.5 \times 10^6 \text{ Hz}
\]
Now, we substitute the values into the wavelength formula:
\[
\lambda = \frac{3 \times 10^8 \text{ m/s}}{101.5 \times 10^6 \text{ Hz}}
\]
Calculating this gives:
\[
\lambda \approx \frac{3 \times 10^8}{101.5 \times 10^6} \approx \frac{3 \times 10^8}{1.015 \times 10^8} \approx 2.95 \text{ m}
\]
After rounding, we find:
\[
\lambda \approx 2.96 \text{ m}
\]
Therefore, the correct answer is:
**2.96 m**