Asked by SkatingDJ

Radio signals travel at a rate of 3 * 10^8 meters per second. How many seconds would it take for a radio signal to travel from a satellite to the surface of Earth if the satellite is orbiting at a height of 9.6 * 10^6 meters? (1 point)

3.2 x 10^2 seconds
3.2 x 10^-2 seconds
3.13 x 10^1 seconds
2.88 x 10^15 seconds

I think I'm close to getting it... but I'm still not quite sure. Please help?
Answered by PsyDAG
10^6/10^8 = 10^-2
Answered by SkatingDJ
Great, thanks so much:) I was debating if it was the -2 or the positive 2 exponent. Thanks again!
Answered by So
So is SkatingDJ right?
Answered by So
I meant PsyDAG
Answered by Oof
Hello. Mine's different...

Radio signals travel at a rate of 3 x 10^8 meters per second. How many seconds will it take for a radio signal to travel from a satellite to the surface of the Earth if the satellite is orbiting at a height of 3.6 x 10^9 meters?
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