Suppose you had a mixture consisting of 20.0 g of compound A and 20.0 g of compound B dissolved in 100.0 mL of water at 95 degrees C. Suppose further that only 1.00 g of A are soluble in 100.0 mL of water at 5 degrees C but 15.0 g of B are soluble in 100.0 mL of water at 5 degrees C. What is the mass ratio of A to B in the 95 degree C mixture before recrystallization?

Question

Suppose you had a mixture consisting of 20.0 g of compound A and 20.0 g of compound B dissolved in 100.0 mL of water at 95 degrees C. Suppose further that only 1.00 g of A are soluble in 100.0 mL of water at 5 degrees C  but 15.0 g of B are soluble in 100.0 mL of water at 5 degrees C.  What is the mass ratio of A to B in the 95 degree C mixture before recrystallization?

DrBob222 · Answer

Am I missing something? 20.0 g A and 20.0 g B @ 95C is a 1:1 ratio A/B. It appears to me that everything after the first sentence is superfluous information.

Olorunto micheal · Answer

So simple