Question

Suppose 5.00 gram of a mixture of aspirin, caffeine, and acetanilide was dissolved in enough solvent (methylene chloride) to make a total of 100.00 mL volume. You took 10.00 mL from it and isolated its components using the same protocol you did in the lab. You obtained:
Aspirin (180.16 g/mol ) = 0.082 gram; Caffeine (194.19 g/mol ) = 0.21 gram; acetanilide (135.16 g/mol )= 0.150 g
1. What is the % of each component in the original mixture?
2. If the total number of moles of components in 5.00 gram of the mixture is 0.600 mole, what is the molar % composition of each component in the mixture?

Answer 1

% aspirin = (0.082/5.00)*100 = ?
%caffeine = )0.21/5.00)*100 = ?d
etc for acetanilide.

For #2, convert grams given in the problem to mols. mol = grams/molar mass = ?
Then mol% aspirin = (mols aspirin/0.600)*100 = ?
etc. for the others.