P = 2L + 2W
W = L - 3
P = 2L + 2(L - 3)
130 = 4L - 6
136 = 4L
34 = L
W = 31
The width of a rectangle is 3 yards less than its length. the perimeter is 130 yards. Find the length and width of the rectangle
2 answers
width --- x
length --- x-3
solve
2x + 2(x-3) = 130
length --- x-3
solve
2x + 2(x-3) = 130