Asked by Amy
Given AB is perpendicular to BC
<ABO= (2x + y)degrees
<OBC= (6x + 8)deg.
<AOB= (23 + 90)deg
<BOC= (4x + 4)degrees
Find <ABO
(don't know how to draw it but a triangle is within a circle. The triangle name is ABC and segment BO goes through the triangle.)
<ABO= (2x + y)degrees
<OBC= (6x + 8)deg.
<AOB= (23 + 90)deg
<BOC= (4x + 4)degrees
Find <ABO
(don't know how to draw it but a triangle is within a circle. The triangle name is ABC and segment BO goes through the triangle.)
Answers
Answered by
Reiny
Confusing question.
You say "a triangle is within a circle"
Are the vertices on the triangle ON the circle?
Where does O come in ? Is O the centre of the circle?
also the statement
<AOB= (23 + 90)deg looks like a typo, all the others contain variable names.
You say "a triangle is within a circle"
Are the vertices on the triangle ON the circle?
Where does O come in ? Is O the centre of the circle?
also the statement
<AOB= (23 + 90)deg looks like a typo, all the others contain variable names.
Answered by
austin
no the vertices is on the point. the 0 i in the center of the circle.
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