Question
Find the domain of the following rational function.
Upper H left parenthesis x right parenthesis equals StartFraction 20 x squared plus x Over x squared plus 10 EndFraction
Question content area bottom
Part 1
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A.
The domain of H(x) is restricted to
enter your response here.
(Type your answer in interval notation.)
B.
There are no restrictions on the domain of H(x).
Upper H left parenthesis x right parenthesis equals StartFraction 20 x squared plus x Over x squared plus 10 EndFraction
Question content area bottom
Part 1
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A.
The domain of H(x) is restricted to
enter your response here.
(Type your answer in interval notation.)
B.
There are no restrictions on the domain of H(x).
Answers
GPT-4o mini
To find the domain of the rational function \( H(x) = \frac{20x^2 + x}{x^2 + 10} \), we need to determine the values of \( x \) for which the function is defined. A rational function is undefined when the denominator is equal to zero.
First, we identify the denominator of the function:
\[
x^2 + 10
\]
Next, we set the denominator equal to zero to find potential restrictions:
\[
x^2 + 10 = 0
\]
We can rearrange this to find:
\[
x^2 = -10
\]
Since \( x^2 \) cannot equal a negative number (as \( x^2 \) is non-negative for all real \( x \)), there are no real solutions to this equation. This means the denominator \( x^2 + 10 \) is never zero for any real number \( x \).
Since the denominator does not equal zero for any real \( x \), there are no restrictions on the domain of \( H(x) \).
Thus, the answer is:
**B. There are no restrictions on the domain of \( H(x) \).**
First, we identify the denominator of the function:
\[
x^2 + 10
\]
Next, we set the denominator equal to zero to find potential restrictions:
\[
x^2 + 10 = 0
\]
We can rearrange this to find:
\[
x^2 = -10
\]
Since \( x^2 \) cannot equal a negative number (as \( x^2 \) is non-negative for all real \( x \)), there are no real solutions to this equation. This means the denominator \( x^2 + 10 \) is never zero for any real number \( x \).
Since the denominator does not equal zero for any real \( x \), there are no restrictions on the domain of \( H(x) \).
Thus, the answer is:
**B. There are no restrictions on the domain of \( H(x) \).**