Question
Find the domain of the following rational function.
g left parenthesis x right parenthesis equals StartFraction negative 7 x squared Over left parenthesis x minus 3 right parenthesis left parenthesis x plus 8 right parenthesis EndFraction
Question content area bottom
Part 1
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A.
The domain of g(x) is restricted to
enter your response here.
(Type your answer in interval notation.)
B.
The domain of g(x) has no restrictions.
g left parenthesis x right parenthesis equals StartFraction negative 7 x squared Over left parenthesis x minus 3 right parenthesis left parenthesis x plus 8 right parenthesis EndFraction
Question content area bottom
Part 1
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A.
The domain of g(x) is restricted to
enter your response here.
(Type your answer in interval notation.)
B.
The domain of g(x) has no restrictions.
Answers
GPT-4o mini
To determine the domain of the rational function \( g(x) = \frac{-7x^2}{(x - 3)(x + 8)} \), we need to identify any values of \( x \) that would make the denominator equal to zero, as these values cannot be included in the domain.
1. The denominator is \( (x - 3)(x + 8) \).
2. Set the denominator equal to zero to find the values we need to exclude:
\[
(x - 3)(x + 8) = 0
\]
This gives us two equations:
- \( x - 3 = 0 \) → \( x = 3 \)
- \( x + 8 = 0 \) → \( x = -8 \)
3. Thus, the values \( x = 3 \) and \( x = -8 \) are not in the domain of \( g(x) \).
4. Since these are the only restrictions, the domain of \( g(x) \) in interval notation is:
\[
(-\infty, -8) \cup (-8, 3) \cup (3, \infty)
\]
So, the correct answer is:
A. The domain of \( g(x) \) is restricted to
\[
(-\infty, -8) \cup (-8, 3) \cup (3, \infty)
\]
1. The denominator is \( (x - 3)(x + 8) \).
2. Set the denominator equal to zero to find the values we need to exclude:
\[
(x - 3)(x + 8) = 0
\]
This gives us two equations:
- \( x - 3 = 0 \) → \( x = 3 \)
- \( x + 8 = 0 \) → \( x = -8 \)
3. Thus, the values \( x = 3 \) and \( x = -8 \) are not in the domain of \( g(x) \).
4. Since these are the only restrictions, the domain of \( g(x) \) in interval notation is:
\[
(-\infty, -8) \cup (-8, 3) \cup (3, \infty)
\]
So, the correct answer is:
A. The domain of \( g(x) \) is restricted to
\[
(-\infty, -8) \cup (-8, 3) \cup (3, \infty)
\]