Question
We did a lab. The reaction of zinc and iodine.
We put 1 g of zinc with 1 g of iodine.. and used alcohol.
Is the equation Zn + I2 ----> ZnI(2)?
The moles of Zn atoms consumed were .003 mol.
The moles of I atoms consumed were .004 mol.
The class got a ratio and we averaged it.. it was 1:1.98
What does this ratio mean? Could someone explain this?
We put 1 g of zinc with 1 g of iodine.. and used alcohol.
Is the equation Zn + I2 ----> ZnI(2)?
The moles of Zn atoms consumed were .003 mol.
The moles of I atoms consumed were .004 mol.
The class got a ratio and we averaged it.. it was 1:1.98
What does this ratio mean? Could someone explain this?
Answers
1:1.98 rounds to 1:2 which means the formula is ZnI2.
Related Questions
Zinc has three major and two minor isotopes. For this problem, assume that the only isotopes of zinc...
3.25g of zinc was added to 50cm^3 of a 4.0 molar dm^-3 HCl. When the reaction was completed the temp...
The synthesis of zinc iodide was performed using 1.8912g of zinc and 1.5965g of iodine. Determine th...
The first step in the process used to recover zinc metal from zinc sulfide ore is the reaction of zi...