Asked by shawn
What is the freezing pint of 0.0091 m aqueous sodium phosphate, Na3PO4? Assume that sodium phosphate is a strong electrolyte and it functions ideally in solution. (express your answer in degrees Celsius)
Answers
Answered by
Mac
I do believe that
Van Hoff = 4
Kf(water) = 1.86
Molality = .0091
4*1.86*0.0091=delta T=.067704
0.00-.067704=-0.0677 degrees C is the answer on Millers quiz
Van Hoff = 4
Kf(water) = 1.86
Molality = .0091
4*1.86*0.0091=delta T=.067704
0.00-.067704=-0.0677 degrees C is the answer on Millers quiz
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