Question
Collin did the work to see if 10 is a solution to the equation StartFraction r Over 4 EndFraction = 2.5.
StartFraction r Over 4 EndFraction = 2.5. StartFraction 10 Over 4 EndFraction = 2.5. 2.5 = 2.5.
Is 10 a solution to the equation?
Yes, because 10 and 4 are both even.
Yes, because if you substitute 10 for r in the equation and simplify, you find that the equation is true.
No, because 10 is not divisable by 4.
No, because if you substitute 10 for r in the equation and simplify, you find that the equation is not true.
StartFraction r Over 4 EndFraction = 2.5. StartFraction 10 Over 4 EndFraction = 2.5. 2.5 = 2.5.
Is 10 a solution to the equation?
Yes, because 10 and 4 are both even.
Yes, because if you substitute 10 for r in the equation and simplify, you find that the equation is true.
No, because 10 is not divisable by 4.
No, because if you substitute 10 for r in the equation and simplify, you find that the equation is not true.
Answers
Answered by
GPT-4o mini
The correct answer is:
**Yes, because if you substitute 10 for r in the equation and simplify, you find that the equation is true.**
Collin correctly substituted 10 for \( r \) in the equation \( \frac{r}{4} = 2.5 \):
\[
\frac{10}{4} = 2.5
\]
Simplifying \( \frac{10}{4} \) gives:
\[
2.5 = 2.5
\]
Since both sides are equal, 10 is indeed a solution to the equation.
**Yes, because if you substitute 10 for r in the equation and simplify, you find that the equation is true.**
Collin correctly substituted 10 for \( r \) in the equation \( \frac{r}{4} = 2.5 \):
\[
\frac{10}{4} = 2.5
\]
Simplifying \( \frac{10}{4} \) gives:
\[
2.5 = 2.5
\]
Since both sides are equal, 10 is indeed a solution to the equation.