Question
Collin is substituting t = 2 and t = 6 to determine if the two expressions are equivalent.
3 (t + 5) 3 t + 5
Which statement is true?
Both expressions are equivalent to 11 when t = 2.
Both expressions are equivalent to 33 when t = 6.
Both expressions are equivalent to 23 when t = 6.
The expressions are not equivalent.
3 (t + 5) 3 t + 5
Which statement is true?
Both expressions are equivalent to 11 when t = 2.
Both expressions are equivalent to 33 when t = 6.
Both expressions are equivalent to 23 when t = 6.
The expressions are not equivalent.
Answers
Answered by
GPT-4o mini
Let's evaluate both expressions \(3(t + 5)\) and \(3t + 5\) for \(t = 2\) and \(t = 6\) to determine if they are equivalent.
**When \(t = 2\):**
1. For the first expression:
\[
3(t + 5) = 3(2 + 5) = 3(7) = 21
\]
2. For the second expression:
\[
3t + 5 = 3(2) + 5 = 6 + 5 = 11
\]
So, when \(t = 2\), the values are:
- \(3(t + 5) = 21\)
- \(3t + 5 = 11\)
They are **not equivalent** when \(t = 2\).
---
**When \(t = 6\):**
1. For the first expression:
\[
3(t + 5) = 3(6 + 5) = 3(11) = 33
\]
2. For the second expression:
\[
3t + 5 = 3(6) + 5 = 18 + 5 = 23
\]
So, when \(t = 6\), the values are:
- \(3(t + 5) = 33\)
- \(3t + 5 = 23\)
They are **not equivalent** when \(t = 6\) either.
---
### Conclusion:
Based on the calculations, the correct statement is:
**The expressions are not equivalent.**
**When \(t = 2\):**
1. For the first expression:
\[
3(t + 5) = 3(2 + 5) = 3(7) = 21
\]
2. For the second expression:
\[
3t + 5 = 3(2) + 5 = 6 + 5 = 11
\]
So, when \(t = 2\), the values are:
- \(3(t + 5) = 21\)
- \(3t + 5 = 11\)
They are **not equivalent** when \(t = 2\).
---
**When \(t = 6\):**
1. For the first expression:
\[
3(t + 5) = 3(6 + 5) = 3(11) = 33
\]
2. For the second expression:
\[
3t + 5 = 3(6) + 5 = 18 + 5 = 23
\]
So, when \(t = 6\), the values are:
- \(3(t + 5) = 33\)
- \(3t + 5 = 23\)
They are **not equivalent** when \(t = 6\) either.
---
### Conclusion:
Based on the calculations, the correct statement is:
**The expressions are not equivalent.**