Question
Use the image to solve the problem below.
the vertex is inbetween 0 and 1
The function shown in the graph is:
(1 point)
Responses
Odd
Odd
Both Even and Odd
Both Even and Odd
Even
Even
Neither Even nor Odd
the vertex is inbetween 0 and 1
The function shown in the graph is:
(1 point)
Responses
Odd
Odd
Both Even and Odd
Both Even and Odd
Even
Even
Neither Even nor Odd
Answers
Answered by
GPT-4o mini
To determine whether a function is even, odd, or neither, we can use the following definitions:
1. A function \( f(x) \) is **even** if \( f(-x) = f(x) \) for all \( x \) in the domain of \( f \). This means the graph is symmetric with respect to the y-axis.
2. A function \( f(x) \) is **odd** if \( f(-x) = -f(x) \) for all \( x \) in the domain of \( f \). This means the graph is symmetric with respect to the origin.
Without the specific graph to analyze, here are some general guidelines:
- If the graph is symmetric about the y-axis, it is even.
- If the graph is symmetric about the origin, it is odd.
- If the graph does not exhibit either symmetry, it is neither.
Since you've noted that "the vertex is between 0 and 1," it is likely that the function has some form of symmetry. However, without seeing the graph, I cannot definitively determine whether the function is even, odd, or neither.
If you describe the graph or provide key features, I can help determine the classification of the function.
1. A function \( f(x) \) is **even** if \( f(-x) = f(x) \) for all \( x \) in the domain of \( f \). This means the graph is symmetric with respect to the y-axis.
2. A function \( f(x) \) is **odd** if \( f(-x) = -f(x) \) for all \( x \) in the domain of \( f \). This means the graph is symmetric with respect to the origin.
Without the specific graph to analyze, here are some general guidelines:
- If the graph is symmetric about the y-axis, it is even.
- If the graph is symmetric about the origin, it is odd.
- If the graph does not exhibit either symmetry, it is neither.
Since you've noted that "the vertex is between 0 and 1," it is likely that the function has some form of symmetry. However, without seeing the graph, I cannot definitively determine whether the function is even, odd, or neither.
If you describe the graph or provide key features, I can help determine the classification of the function.
There are no human answers yet. A form for humans to post answers is coming very soon!