To determine which equation has infinitely many solutions, we need to identify the equations that are equivalent or simplify to a true statement regardless of the value of \( x \).
Let's analyze each option:
-
\( 4x + 1 = 4(x + 1) \):
- Simplifying the right side: \[ 4(x + 1) = 4x + 4 \]
- Thus, the equation becomes: \[ 4x + 1 = 4x + 4 \]
- Subtracting \( 4x \) from both sides: \[ 1 = 4 \] (false)
-
\( 3 - 3x = -3(x - 1) \):
- Simplifying the right side: \[ -3(x - 1) = -3x + 3 \]
- The equation becomes: \[ 3 - 3x = -3x + 3 \]
- Adding \( 3x \) to both sides: \[ 3 = 3 \] (true, so infinitely many solutions)
-
\( 3x = 2x + 1 \):
- Subtracting \( 2x \) from both sides: \[ x = 1 \] (one solution)
-
\( 3x + 5 = 3x - 5 \):
- Subtracting \( 3x \) from both sides: \[ 5 = -5 \] (false)
The only equation that simplifies to a true statement (indicating infinitely many solutions) is:
\( 3 - 3x = -3(x - 1) \).