Let's analyze the given equations to identify which one has infinitely many solutions.
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4x + 1 = 4(x + 1)
Simplifying this:
\( 4x + 1 = 4x + 4 \)
Subtracting \( 4x \) from both sides:
\( 1 = 4 \)
This is a contradiction; hence, no solution. -
3x + 5 = 3x − 5
Simplifying this:
\( 3x + 5 - 3x = -5 \)
\( 5 = -5 \)
This is also a contradiction; hence, no solution. -
3x = 2x + 1
Simplifying this:
\( 3x - 2x = 1 \)
\( x = 1 \)
This gives us a single solution. -
3 − 3x = −3(x − 1)
Simplifying this:
\( 3 - 3x = -3x + 3 \)
Rearranging gives us:
\( 3 = 3 \)
This is always true for any value of \( x \); hence, it has infinitely many solutions.
Based on the analysis above, the equation that has infinitely many solutions is:
3 − 3x = −3(x − 1).
Now, regarding Question 5 about the student's work:
The correct interpretation is that the equation \( 2(2x + 2) = 4(x + 4) \) was simplified to \( 4x + 4 = 4x + 4 \), which leads to \( 4 = 4 \), indicating that it holds true for any \( x \).
Therefore, the equation solved correctly would show that it has infinitely many solution(s).