4) A 1200 kg car is accelerating at 1.6 m/s2. If the coefficient of friction of friction is 0.15, what is the force applied to the car by the engine?
here do you use the equation kinetic friction= μk(normal force) and put in 1.6 m/s^2=.15(Fn) is this how you go about it?
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No. You don't need to know or use the coefficient of friction. Just use Newton's second law: F = m a
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