4.905t^2 + 2.93t - 10 = 0

Question

I have to solve for t.
How do I solve this equation step by step?
Thanks.

Answer 1

Have you ever heard of the quadratic formula? It's the easiest solution here.
In the quadratic formula, for any quadratic equation in the for ax^2+bx+c=0
x=(-b�}�ã(b^2-4ac))/2a
In this case:
4.905=a
2.93=b
-10=c
Think you can solve it from here? The rest is some simple arithmetic (maybe use a calculator, it could be a little easier). Hope this helped. Peace.

Answer 2

I could've solve it if it didn't have decimal. I'd be appreciate if you could solve it form me. Thanks