(4.44e-2 - x) (8.06e-2 - x) / (0.331 + 2x)^2 = 1.80e-2

Question

I need to rearrange this equation so that I can get a,b, and c, for the quadratic equation but I am not sure how to do this. Thank you for the help.

Answer 1

multpily both sides by (.331+2x)^2

now multiply out the left side, getting four terms. On the right, mupltiply all that square term out

Now, collect terms. Put them all on one side, you will have the quadratic form.

It is mostly algebra.

Answer 2

So I have to multiply (4.44e-2 -x )(8.06e-2 - x) by (0.331 + 2x)^2 or am I suppose to multiply 1.80e-2 by it?