4.00L of water was added to 0.400L of an aqueous ethanol solution, giving a final concentration of 0.0400 M. What is the initial concentration of ethanol?
I just need help setting it up pls
Thanks!
2 answers
Never mind I figured it out!
you diluted it by a factor of 11, with one part original, ten parts water.
Then, if the final concentration is.04M, the initial must have been .44M (11 times the final)
Want to do it with Math?
final solute= initial solute
.04M*4.4L=?*.4L
?= .44M
Then, if the final concentration is.04M, the initial must have been .44M (11 times the final)
Want to do it with Math?
final solute= initial solute
.04M*4.4L=?*.4L
?= .44M
2 answers