Asked by Mara
If a rate of 80.0 mL of an aqueous solution of potassium hydroxide concentration of 0.25 mol / L are partially neutralized by 20.0 mL of an aqueous solution of nitric acid concentration of 0.50 mol L. Determine pH of the final solution.
kOH + HNO3 -> H2O + KNO3
kOH + HNO3 -> H2O + KNO3
Answers
Answered by
DrBob222
mols HNO3 = M x L = ?
mols KOH = M x L = ?
Look to see which has more mols then subtract the smaller from the larger. The excess will determine the pH. If acid is in excess then mols excess/total volume in L = (H^+) and convert to pH.
If KOH is in excess then excess/total volume in L = OH, convert to pOH and pH. Post your work if you get stuck
mols KOH = M x L = ?
Look to see which has more mols then subtract the smaller from the larger. The excess will determine the pH. If acid is in excess then mols excess/total volume in L = (H^+) and convert to pH.
If KOH is in excess then excess/total volume in L = OH, convert to pOH and pH. Post your work if you get stuck
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